This is a pretty basic poker equition, but it will eventually become part of a larger project. I’m putting it here because I managed to mess it up twice and would really like to have the correct version in the future.

EV = our expected value

f = probability our opponent folds to our bet

p = current pot (before our bet)

*Note: I’m completely ignoring any further play*

EV = (fold equity) + (SD equity given call)

EV = f*p + (1-f)*(SD equity)

EV = f*(p – (SD equity)) + (SD equity)

We of course want EV > 0, so

f*(p – (SD equity)) + (SD equity) > 0

f > -(SD equity)/(p – (SD equity))

(SD equity)/(SD equity – p)” width=”147″ height=”41″ />

To make this equation complete, let

w = probability of winning at showdown when called

b = our bet

then,

These equations make sense because:

- When we have 0% chance to win if called, our showdown equity is –b, so we have:

*f > b/(b+p)*
- On the other hand, when we have a lock (100% chance to win), our equity is p+b (the pot plus opponent’s call), so we have:

*f > (p+b)/(p+b-p) = (p+b)/b*, which means we never want the villain to fold
- This also tells us that the result “f > 1” lies somewhere between 0% and 100% to win. This is obviously because of pot odds, since we win
*(p+b)*, but lose only *b*, we don’t actually need a lock to want the villain to call every time (ex: when you have straight vs set, you never want opponent to fold, even though a set will suck out quite often)

Related Post: Chart of Required Fold Equity

Filed under: Poker Math | Tagged: fold equity, poker, Poker Math, showdown equity, white and nerdy | 1 Comment »